#include<bits/stdc++.h> using namespace std; int main() { int a,b,c,d,e; cin>>a>>b>>c>>d>>e; a=a/3; b=b+a; e=e+a; b=b/3; a=b+a; c=c+b; c=c/3; b=c+b; d=c+d; d=d/3; c=c+d; e=e+d; e=e/3; d=d+e; a=a+e; cout<<a<<" "<<b<<" "<<c<<" "<<d<<" "<<e; return 0; }

思路

What a 数组练习水题！ 因为 5 个人围成了一个圈，不妨设 $a_{(i+4) \bmod 5}$ 为 $a_i$ 前面的，$a_{(i+1)\bmod 5}$ 为 $a_i$ 后面的，这样就好办了。

code

#include<bits/stdc++.h>
using namespace std;
int a[7];
int main(){
	for(int i=0;i<5;i++){
		cin>>a[i];
	}
	for(int i=0;i<5;i++){
		a[i]/=3;
		a[(i+4)%5]+=a[i];
		a[(i+1)%5]+=a[i];
	}
	for(int i=0;i<5;i++){
		cout<<a[i]<<' ';
	}
	return 0;
}

#include<bits/stdc++.h> using namespace std; int main() { int a,b,c,d,e; cin>>a>>b>>c>>d>>e; a=a/3, a=b+a, b=b/3, b=b+c, c=c/3, c=c+d, d=d/3, d=d+e, e=e/3, e=e+a, cout<<a<<" "<<b<<" "<<c<<" "<<d<<" "<<e; return 0; }

#include<bits/stdc++.h> using namespace std; int main() { int a,b,c,d,e; cin>>a>>b>>c>>d>>e; a=a/3;b=b+a;e=e+a; b=b/3;a=a+b;c=c+b; c=c/3;d=d+c;b=b+c; d=d/3;e=e+d;c=c+d; e=e/3;a=a+e;d=d+e; cout<<a<<" "<<b<<" "<<c<<" "<<d<<" "<<e; return 0; }

#include<bits/stdc++.h> 
using namespace std; 
int main() 
{
 int a,b,c,d,e; 
 cin>>a>>b>>c>>d>>e; 
 a=a/3; 
 b=b+a; 
 e=e+a; 
 b=b/3; 
 a=b+a; 
 c=c+b; 
 c=c/3; 
 b=c+b; 
 d=c+d; 
 d=d/3; 
 c=c+d; 
 e=e+d; 
 e=e/3; 
 d=d+e; 
 a=a+e; 
 cout<<a<<" "<<b<<" "<<c<<" "<<d<<" "<<e; 
 return 0; 
}

#include<iostream> using namespace std; int main() { int a,b,c,d,e; cin>>a>>b>>c>>d>>e; a=a/3; b=b+a; e=e+a; b=b/3; a=a+b; c=c+b; c=c/3; b=c+b; d=c+d; d=d/3; c=c+d; e=d+e; e=e/3; d=d+e; a=a+e; cout<<a<<" "<<b<<" "<<c<<" "<<d<<" "<<e; return 0; }