思路

翻译一下：求高为 $a$ ，半径为 $b$ 的圆柱表面积。

$$\begin{aligned} S_{\text{总}}&=2S_{\text{底}}+S_{\text{侧}}\\ &=2 \pi b^2+2 \pi b \times a\\ &=2\pi b(b+a) \end{aligned}$$

code

#include<bits/stdc++.h>
using namespace std;
int a,b;
const double PI=3.1415926;
int main(){
	cin>>a>>b;
	printf("%.3f",2*PI*b*(a+b));
	return 0;
}

#include<bits/stdc++.h> using namespace std; const double pi=3.1415926; int main() { double a,b,c; cin>>a>>b; c=2bpia+2bbpi; cout<<fixed<<setprecision(3)<<c<<endl; return 0; }

#include<bits/stdc++.h> using namespace std; int main() { int a,b; cin>>a>>b; const double PI=3.1415926; cout<<fixed<<setprecision(3)<<PI2b*(b+a); return 0; }

#include<bits/stdc++.h> using namespace std; int main() { int a,b; cin>>a>>b; const double PI=3.1415926; cout<<fixed<<setprecision(3)<<2PIba+PIbb2; return 0; }

👍 #include<bits/stdc++.h> using namespace std; int main() { int a,b; cin>>a>>b; const double pi=3.1415926; cout<<fixed<<setprecision(3)<<2pi(bb+ab); return 0; }

#include<iostream> #include<iomanip> using namespace std; int main() { double a,b,c,d,e,f,g,z; cin>>a>>b; z=3.1415926; c=zbb; d=c2; e=2bz; f=ea; g=d+f; cout<<fixed<<setprecision(3)<<g; return 0; }

#include<iostream> #include<iomanip> using namespace std; int main() { double a,b,c,d,e,f,g,z; cin>>a>>b; z=3.1415926; c=zbb; d=c2.000; e=2bz; f=ea; g=d+f; cout<<fixed<<setprecision(3)<<g; return 0; }