题解 - 平均分

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Guest
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Guest @ 2025-8-29 2:05:21

555
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励志当程序员 LV 6 @ 2024-11-5 13:46:50

#include<bits/stdc++.h> using namespace std; int main() { double x,y,a; cin>>x>>y; a=(87x+85y)/(x+y); cout<<fixed<<setprecision(2)<<a<<endl; return 0; }
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再用scanf就是乐子^^ (zjs) LV 10 @ 2024-10-10 20:30:33
思路

根据平均分计算公式可知，答案为：

$(x \times 87.0+y \times 85.0)/(x+y)$

code
```
#include<bits/stdc++.h>
using namespace std;
int main(){
   int x,y;
   cin>>x>>y;
   printf("%.2lf",(x*87.0+y*85.0)/(x+y));
   return 0;
}
```

zhoulinzheng LV 3 @ 2023-12-24 12:52:02

#include<bits/stdc++.h>
 using namespace std; 
double x,y;
int main() 
{ cin>>x>>y;
 cout<<fixed<<setprecision(2)<<(87.00*x+85.00*y)/(x+y);
 return 0; 
}

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24BDQS LV 6 @ 2024-11-5 13:35:05

#include<bits/stdc++.h> using namespace std; int main () { double x,y; cin>>x>>y; cout<<fixed<<setprecision(2)<<(x87+y85)/(x+y); return 0; }
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sxy018400 LV 6 @ 2023-12-22 13:55:21

#include<bits/stdc++.h> using namespace std; double x,y; int main() { cin>>x>>y; cout<<fixed<<setprecision(2)<<(87x+85y)/(x+y); return 0; }